JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    Capacitance (in F) of a spherical conductor with radius 1 m is

    A) \[1.1\times {{10}^{-10}}\]

    B) \[{{10}^{6}}\]

    C) \[9\times {{10}^{-9}}\]

    D) \[{{10}^{-3}}\]

    Correct Answer: A

    Solution :

    [a] Capacitance of spherical conductor \[4\pi {{\varepsilon }_{0}}a\] where a is radius of conductor. Therefore, \[C=\frac{1}{9\times {{10}^{9}}}\times 1=\frac{1}{9}\times {{10}^{-9}}\] \[=0.11\times {{10}^{-9}}F=1.1\times {{10}^{-10}}F\]


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