JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    The work done in placing a charge of \[8\times {{10}^{-18}}\]coulomb on a condenser of capacity 100 microfarad is

    A) \[3.1\times {{10}^{-26}}joule\]

    B)        \[4\times {{10}^{-10}}joule\]

    C) \[3.2\times {{10}^{-32}}joule\] 

    D) \[16\times {{10}^{-32}}joule\]

    Correct Answer: C

    Solution :

    [c] Work done\[=\frac{1}{2}\frac{{{q}^{2}}}{C}=\frac{{{\left( 8\times {{10}^{-18}} \right)}^{2}}}{2\times 10\times {{10}^{-6}}}\] \[=32\times {{10}^{-32}}J\]


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