JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

    A) 8 times

    B) 4 times

    C) 2 times

    D) 32 times

    Correct Answer: C

    Solution :

    [c] Volume of 8 small drops = Volume of big drop \[8\times \frac{4}{3}\pi {{R}^{3}}=\frac{4}{3}\pi {{R}^{3}}\Rightarrow R=2r\] As capacity is proportional to r, hence capacity becomes 2 times.


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