JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    Two concentric conducting spherical shells of radii \[{{a}_{1}}\]and \[{{a}_{2}}\]\[({{a}_{2}}>{{a}_{1}})\] are charged to potentials \[{{\phi }_{1}}\] and \[{{\phi }_{2}}\], respectively. Find the charge on the inner shell.

    A) \[{{q}_{1}}=4\pi {{\varepsilon }_{0}}\left( \frac{{{\phi }_{1}}-{{\phi }_{2}}}{{{a}_{2}}-{{a}_{1}}} \right){{a}_{1}}{{a}_{2}}\]      

    B) \[{{q}_{1}}=4\pi {{\varepsilon }_{0}}\left( \frac{{{\phi }_{1}}+{{\phi }_{2}}}{{{a}_{2}}+{{a}_{1}}} \right){{a}_{1}}{{a}_{2}}\]

    C) \[{{q}_{1}}=4\pi {{\varepsilon }_{0}}\left( \frac{{{\phi }_{1}}-{{\phi }_{2}}}{{{a}_{2}}+{{a}_{1}}} \right){{a}_{1}}{{a}_{2}}\]

    D) \[{{q}_{1}}=4\pi {{\varepsilon }_{0}}\left( \frac{{{\phi }_{1}}+{{\phi }_{2}}}{{{a}_{2}}-{{a}_{1}}} \right){{a}_{1}}{{a}_{2}}\]

    Correct Answer: A

    Solution :

    [a] \[{{\phi }_{1}}=\frac{k{{q}_{1}}}{{{a}_{1}}}+\frac{k{{q}_{2}}}{{{a}_{2}}}\] \[{{\phi }_{2}}=\frac{k{{q}_{1}}}{{{a}_{2}}}+\frac{k{{q}_{2}}}{{{a}_{2}}}\] Solve to get \[{{q}_{1}}=4\pi {{\varepsilon }_{0}}\left[ \frac{{{\phi }_{1}}-{{\phi }_{2}}}{{{a}_{2}}-{{a}_{1}}} \right]{{a}_{1}}{{a}_{2}}\]


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