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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    A charge of 3 coulomb moving in uniform electric field experiences a force of 3000 newton. The potential difference between the two points situated in a field at a distance of 1 cm from each other will be:

    A) 100      

    B) 5000

    C) 10

    D) 50

    Correct Answer: C

    Solution :

    [c] Force on a charge m an electric field is \[F=qE\] But \[E=\frac{V}{d}\text{          }\therefore F=\frac{qV}{d}\] \[\text{or  }V=\frac{Fd}{q}=\frac{300N\times 1\times {{10}^{-2}}m}{3C}=10volt\]


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