JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d. If the potential difference between the plates is V, the time taken by the electron to reach the upper plate is given charge on C is           

    A) \[\sqrt{\frac{2m{{d}^{2}}}{eV}}\]

    B) \[\sqrt{\frac{m{{d}^{2}}}{eV}}\]

    C) \[\sqrt{\frac{m{{d}^{2}}}{2eV}}\]

    D) \[\frac{2m{{d}^{2}}}{eV}\]

    Correct Answer: A

    Solution :

    [a] \[E=\frac{V}{d},F=eE=eV/d\] \[a=\frac{F}{m}=\frac{eV}{md}\] \[d=\frac{1}{2}a{{t}^{2}}\text{ or }t=\sqrt{\frac{2d}{a}}\] \[\text{or }t=\sqrt{\frac{2dmd}{eV}}=\sqrt{\frac{2m{{d}^{2}}}{eV}}\]


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