JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    There is an infinite straight chain of alternating charges q and -q. The distance between the two neighboring charges is equal to a. Find the interaction energy of any charge with all the other charges.

    A) \[-\frac{2{{q}^{2}}}{4\pi {{\varepsilon }_{0}}a}\]

    B) \[\frac{2{{q}^{2}}{{\log }_{e}}2}{4\pi {{\varepsilon }_{0}}a}\]

    C) \[-\frac{2{{q}^{2}}{{\log }_{e}}2}{4\pi {{\varepsilon }_{0}}a}\]

    D) Zero

    Correct Answer: C

    Solution :

    [c] \[U=2k{{q}^{2}}\left[ -\frac{1}{a}+\frac{1}{2a}-\frac{1}{3a}+\frac{1}{4a}+..... \right]\]


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