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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass \[1.96\times {{10}^{-15}}kg\] is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is

    A) 8

    B) 6

    C) 0.1

    D) 3

    Correct Answer: D

    Solution :

    [d]  In equilibrium, \[F=qE=\left( ne \right)\frac{V}{d}=mg\] \[n=\frac{mgd}{eV}=\frac{1.96\times {{10}^{-15}}\times 9.8\times 0.02}{1.6\times {{10}^{-19}}\times 800}=3\]


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