A) \[{{\left[ \frac{K{{q}^{2}}}{mL}\left( 5.4 \right) \right]}^{1/2}}\]
B) \[{{\left[ \frac{K{{q}^{2}}}{mL}\left( 1.35 \right) \right]}^{1/2}}\]
C) \[{{\left[ \frac{K{{q}^{2}}}{mL}\left( 2.7 \right) \right]}^{1/2}}\]
D) None of these
Correct Answer: C
Solution :
[c] Potential energy of the system \[4\times \frac{K}{2}\left( \frac{{{q}^{2}}}{L}+\frac{{{q}^{2}}}{L}+\frac{{{q}^{2}}}{L\sqrt{2}} \right)=5.4\frac{K{{q}^{2}}}{L}\] = Final kinetic energy of the system = \[4\times \frac{1}{2}m{{v}^{2}}=2m{{v}^{2}}\] \[\therefore v={{\left[ \frac{K{{q}^{2}}}{mL}\left( 2.7 \right) \right]}^{1/2}}\]
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