JEE Main & Advanced Physics EM Waves Question Bank Self Evaluation Test - Electromagnetic Waves

  • question_answer
    A plane electromagnetic wave propagating in the X-direction has wavelength of\[6.0\text{ }mm\]. The electric field is in the Y-direction and its maximum magnitude is\[33\text{ }V{{m}^{-1}}\]. The equation for the electric field as a function of x and t is

    A) \[11\,\sin \pi \left( t-\frac{x}{c} \right)\]

    B)        \[33\sin \left[ \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right) \right]\]

    C) \[33\sin \,\pi \left( t-\frac{x}{c} \right)\]

    D) \[11\sin \,\left[ \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right) \right]\]

    Correct Answer: B

    Solution :

    [b] \[\omega =2\pi v=\frac{2\pi c}{\lambda }=\frac{2\pi \times 3\times {{10}^{8}}}{6\times {{10}^{-3}}}\] \[=\pi \times {{10}^{11}}\,rad/\sec \] The equation for the electric field, along y-axis in the electromagnetic wave is \[Ey={{E}_{0}}\,\sin \,\omega \left( t-\frac{x}{c} \right)=33\sin \left[ \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right) \right]\]


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