A) \[(2\hat{i}+3\hat{j})\] and \[(\hat{i}+2\hat{j})\]
B) \[(-2\hat{i}-3\hat{j})\] and \[(3\hat{i}-2\hat{j})\]
C) \[(3\hat{i}+4\hat{j})\] and \[(4\hat{i}-3\hat{j})\]
D) \[(\hat{i}+2\hat{j})\] and \[(2\hat{i}-\hat{j})\]
Correct Answer: B
Solution :
[b] As we know, \[\vec{E}.\vec{B}=0\] \[\because \,\,[\vec{E}\bot \vec{B}]\] and\[\vec{E}\times \vec{B}\] should be along Z direction As \[(-2\hat{i}-3\hat{j})\times (3\hat{i}-2\hat{j})=5\hat{k}\] Hence option is the correct answer.You need to login to perform this action.
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