A) \[B={{10}^{-3}}\,\sin \,\left[ \frac{2\pi }{5\times {{10}^{-3}}}(ct-x) \right]\]
B) \[B={{10}^{-7}}\,\sin \,\left[ \frac{2\pi }{5\times {{10}^{-3}}}(ct-x) \right]\]
C) \[B={{10}^{-5}}\,\sin \,\left[ \frac{\pi }{1.5\times {{10}^{-3}}}(ct-x) \right]\]
D) None of these
Correct Answer: B
Solution :
[b] \[E={{E}_{0}}\sin \,\omega \left( t-\frac{x}{c} \right)\]; \[B={{B}_{0}}\sin \omega \left( t-\frac{x}{c} \right)\] \[{{I}_{d}}={{I}_{0}}\sin \left( \omega t+\frac{\pi }{2} \right)=I\] and \[\omega =2\pi v=\frac{2\pi }{\lambda }c\] \[{{E}_{0}}=30\sin \left[ \frac{2\pi }{5\times {{10}^{-3}}}(ct-x) \right]\]and\[{{B}_{0}}=\frac{{{E}_{0}}}{C}={{10}^{-7}}T\] \[B={{B}_{0}}\sin \left[ \frac{2\pi }{\lambda }(ct-x) \right]={{10}^{-7}}\sin \left[ \frac{2\pi }{5\times {{10}^{-3}}}(ct-x) \right]\]You need to login to perform this action.
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