JEE Main & Advanced Physics EM Waves Question Bank Self Evaluation Test - Electromagnetic Waves

  • question_answer
    The amplitude of the electric field if the intensity of a plane electromagnetic wave is given as \[2.0\,W{{m}^{-2}}\] is

    A) \[38.8\,N{{C}^{-1}}\]

    B) \[48.3\,N{{C}^{-1}}\]

    C) \[50.2\,N{{C}^{-1}}\]

    D) \[68.8\,N{{C}^{-1}}\]

    Correct Answer: A

    Solution :

    [a] Intersity of a plane electromagnetic wave \[=\frac{1}{2}{{\varepsilon }_{0}}E_{0}^{2}c\], so \[E=\sqrt{\frac{2I}{{{\varepsilon }_{0}}c}}=38.8\,N{{C}^{-1}}\]


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