A) \[1.6\,J\,{{m}^{-3}}\]
B) \[0.16\,J\,{{m}^{-3}}\]
C) \[0.016\,J\,{{m}^{-3}}\]
D) \[0.0016\,J\,{{m}^{-3}}\]
Correct Answer: C
Solution :
[c] Average energy density corresponding to maximum electric field, \[{{u}_{av}}=\frac{B_{0}^{2}}{2{{\mu }_{0}}}=\frac{{{(200\times {{10}^{-6}})}^{2}}}{2\times 4\pi \times {{10}^{-7}}}\cong 0.016\,J{{m}^{-3}}\]
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