JEE Main & Advanced Physics EM Waves Question Bank Self Evaluation Test - Electromagnetic Waves

  • question_answer
    In an apparatus, the electric field was found to oscillate with an amplitude of\[24\text{ }V/m\]. The magnitude of the oscillating magnetic field will be

    A) \[6\times {{10}^{-6}}T\]

    B) \[2\times {{10}^{-8}}T\]

    C) \[8\times {{10}^{-8}}T\]

    D) \[12\times {{10}^{-6}}T\]

    Correct Answer: C

    Solution :

    [c] \[\frac{E}{B}=C\Rightarrow B=\frac{E}{C}=\frac{24}{3\times {{10}^{8}}}=8\times {{10}^{-8}}T\]


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