A) \[2.7\times {{10}^{12}}T\]
B) \[9.0\times {{10}^{-3}}T\]
C) \[3.0\times {{10}^{-4}}T\]
D) \[3.0\times {{10}^{-5}}T\]
Correct Answer: D
Solution :
[d] \[{{B}_{0}}=\frac{{{E}_{0}}}{c}=\frac{9\times {{10}^{3}}}{3\times {{10}^{8}}}=3\times {{10}^{-5}}T\].
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