question_answer

A rectangular loop has a sliding connector PQ of length \[\ell \] and resistance \[R\,\Omega \] and it is moving with a speed v as shown. The set-up is placed in a uniform magnetic field going m to the plane of the paper. The three currents \[{{I}_{1}},\,{{I}_{2}}\] and / are

A) \[{{I}_{1}}=-{{I}_{2}}=\frac{Blv}{6R},\,I=\frac{2Blv}{6R}\]

B) \[{{I}_{1}}={{I}_{2}}=\frac{Blv}{3R},\,I=\frac{2Blv}{3R}\]

C) \[{{I}_{1}}={{I}_{2}}=I=\frac{Blv}{R}\]

D) \[{{I}_{1}}={{I}_{2}}=\frac{Blv}{6R}\], \[I=\frac{Blv}{3R}\]