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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electric Chages and Fields

  • question_answer
    A loop of diameter d is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be \[\phi .\] What is the electric field strength?

    A) \[\frac{4\phi }{\pi {{d}^{2}}}\]

    B) \[\frac{2\phi }{\pi {{d}^{2}}}\]

    C) \[\frac{\phi }{\pi {{d}^{2}}}\]  

    D) \[\frac{\pi \phi {{d}^{2}}}{4}\]

    Correct Answer: A

    Solution :

    [a] \[\phi \,=E\,A\,\cos \,0{}^\circ \,=E\,\times \frac{\pi \,{{d}^{2}}}{4},\,\,\,\,\,\,\,\therefore \,E=\frac{4\,\phi }{\pi \,{{d}^{2}}}\]


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