A) \[\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}\]
B) \[\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{e}^{2}}}{{{d}^{2}}}}\]
C) \[\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}\]
D) \[\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{q}^{2}}}\]
Correct Answer: C
Solution :
[c] Let n be the number of electrons missing. \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{d}^{2}}}\Rightarrow q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne\] \[\therefore n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}\]You need to login to perform this action.
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