JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electric Chages and Fields

  • question_answer
      Point charge q moves from point P to point S along the path PQRS (as shown in fig.) in a uniform electric field E pointing co-parallel to the positive direction of X-axis. The coordinates of the points P, Q, R and S are (a, b, 0), (2a, 0, 0), (a, -b, 0) and (0, 0, 0) respectively. The work done by the field in the above case is given by the expression

    A) \[qEA\]

    B) \[-qEA\]

    C) \[qEA\sqrt{2}\]

    D) \[qE\sqrt{\left[ {{\left( 2a \right)}^{2}}+{{b}^{2}} \right]}\]

    Correct Answer: B

    Solution :

    [b] \[w=\vec{F}.\vec{s}=Eq\hat{i}.\left( -a\hat{i}-b\hat{j} \right)=-Eqa\]


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