JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electric Chages and Fields

  • question_answer
    A liquid drop having 6 excess electrons is kept stationary under a uniform electric field of\[25.5KV{{m}^{-1}}\]. The radius of the drop is (neglect buotany)

    A) \[4.3\times {{10}^{-7}}m\]

    B) \[7.3\times {{10}^{-7}}m\]

    C) \[0.078\times {{10}^{-7}}m\]

    D) \[3.4\times {{10}^{-7}}m\]

    Correct Answer: B

    Solution :

    [b] \[F=qE=mg\,(q=6e=6\times 1.6\times {{10}^{-19}})\] Density [d] \[\frac{\text{mass}}{\text{volume}}=\frac{m}{\frac{4}{3}\pi {{r}^{3}}}\text{ or }{{r}^{3}}=\frac{m}{\frac{4}{3}\pi d}\] Putting the value of v and m (= 2E/g) and solving we get \[r=7.8\times {{10}^{-7}}m\]


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