A) \[1.13\times {{10}^{11}}\]
B) \[1.13\times {{10}^{10}}\]
C) \[0.61\times {{10}^{11}}\]
D) \[0.61\times {{10}^{9}}\]
Correct Answer: A
Solution :
[a] Here, \[q=1C,{{\varepsilon }_{0}}=8.85\times {{10}^{-12}}{{C}^{2}}{{N}^{-1}}{{m}^{-2}}\] Number of lines of force=Electric force \[=\frac{q}{{{\varepsilon }_{0}}}=\frac{1}{8.85\times {{10}^{-12}}}=1.13\times {{10}^{11}}\]
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