A) \[8\pi \sqrt{{{\in }_{0}}\,{{r}^{3}}(7\Pr +12T)}\]
B) \[8\pi \sqrt{{{\in }_{0}}{{r}^{2}}(7\Pr +12T)}\]
C) \[8\pi \sqrt{{{\in }_{0}}{{r}^{3}}(6\Pr +12T)}\]
D) \[\ell \]
Correct Answer: A
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