A) \[\frac{{{R}_{1}}-{{R}_{2}}+\sqrt{R_{1}^{2}+R_{2}^{2}+6{{R}_{1}}{{R}_{2}}}}{2}\]
B) \[\frac{{{R}_{1}}+{{R}_{2}}+\sqrt{R_{1}^{2}+R_{2}^{2}+6{{R}_{1}}{{R}_{2}}}}{2}\]
C) \[\frac{{{R}_{1}}-{{R}_{2}}-\sqrt{R_{1}^{2}+R_{2}^{2}+6{{R}_{1}}{{R}_{2}}}}{2}\]
D) None of these
Correct Answer: A
Solution :
[a] It follows from symmetry considerations that if we remove the first element from the circuit, the resistance of the remaining circuit between points C and D will be \[{{R}_{CD}}=k{{R}_{AB}}.\] Therefore, the equivalent circuit of the infinite chain will have the form shown in figure.You need to login to perform this action.
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