A) 2, 2, 2
B) 2, 2, no isomerism
C) 3, 2, 2
D) 2, 3, no isomerism
Correct Answer: B
Solution :
[b] The number of geometrical isomers \[{{[Co{{(N{{H}_{3}})}_{2}}{{(Cl)}_{4}}]}^{-}}-2\] \[AuC{{l}_{2}}B{{r}_{2}}-2\] \[{{\left[ Co\left( N{{O}_{2}} \right){{\left( N{{H}_{3}} \right)}_{5}} \right]}^{2+}}\]- No isomerismYou need to login to perform this action.
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