JEE Main & Advanced Chemistry Classification of Elements and Periodicity in Properties / तत्त्वों का वर्गीकरण एवं गुणों में आवर्ति Question Bank Self Evaluation Test - Classification of Elements and Periodicity in Properties

  • question_answer
    The electron affinity of chlorine is 3.7 eV. 1 g of chlorine is completely converted to \[C{{l}^{-}}\]ion in a gaseous state.\[\left( 1\text{ }eV=23.06\,Kcal\text{ }mo{{l}^{-1}} \right)\]. Energy released in the process is

    A) 4.8 kcal            

    B) 7.2 kcal

    C) 8.2 kcal            

    D) 2.4 kcal

    Correct Answer: D

    Solution :

    [d] Number of moles \[=\frac{1}{35.5}\] Given, \[1eV=23.06\text{ }kcal\text{ }mo{{l}^{-1}}\] \[3.7\text{ }eV=3.7\times 23.06\text{ }kcal\text{ }mo{{l}^{-1}}\] i.e. 1 mole release energy \[=3.7\times 23.06\text{ }kcal\] \[\therefore \] Energy released \[=\frac{1}{35.5}\times 3.7\times 23.06\text{ }kcal=2.4\text{ }kcal\]


You need to login to perform this action.
You will be redirected in 3 sec spinner