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JEE Main & Advanced Chemistry Classification of Elements and Periodicity in Properties / तत्त्वों का वर्गीकरण एवं गुणों में आवर्ति Question Bank Self Evaluation Test - Classification of Elements and Periodicity in Properties

  • question_answer
    Aqueous solutions of two compounds \[{{M}_{1}}-O-H\] and \[{{M}_{2}}-O-H\] are prepared in two different beakers. If, the electronegativity of \[{{M}_{1}}=3.4,\]\[{{M}_{2}}=1.2,\,\,O=3.5\] and \[H=2.1\] then the nature of two solutions will be respectively:

    A) acidic, basic   

    B) acidic, acidic

    C) basic, acidic                  

    D) basic, basic

    Correct Answer: A

    Solution :

    [a] The electronegativity difference between \[{{M}_{1}}\]and O is 0.1, which indicates\[{{M}_{1}}-O\] bond will be covalent, since \[O-H\]bond having more ionic character thus bond will break and \[{{H}^{+}}\] ions gets release and acidic solution is formed and whereas difference between electronegativity of \[{{M}_{2}}O\] is 2.3, thus,\[{{M}_{2}}-OH\] bond will break. Hence, solution will be basic in nature.


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