| (1) \[M\left( s \right)\xrightarrow{{}}M\left( g \right)\] |
| (2) \[M(s)\xrightarrow{{}}{{M}^{2+}}(g)+2{{e}^{-}}\] |
| (3) \[M(g)\xrightarrow{{}}{{M}^{+}}(g)+{{e}^{-}}\] |
| (4) \[{{M}^{+}}(g)\xrightarrow{{}}{{M}^{2+}}(g)+{{e}^{-}}\] |
| (5) \[M\left( g \right)\xrightarrow{{}}{{M}^{2+}}\left( g \right)+2{{e}^{-}}\] |
| The second ionization energy of M could be calculated from the energy values associated with: |
A) \[1+3+4\]
B) \[~2-1+3\]
C) \[1+5\]
D) \[5-3\]
Correct Answer: D
Solution :
[d] Second ionization energy is amount of energy required to take out an electron from the monopositive cation.
You need to login to perform this action.
You will be redirected in
3 sec
