A) \[NO\to N{{O}^{+}}\]
B) \[{{N}_{2}}\to N_{2}^{+}\]
C) \[{{C}_{2}}\to {{C}_{2}}^{+}\]
D) \[{{O}_{2}}\to {{O}_{2}}^{+}\]
Correct Answer: A
Solution :
[a] For NO Total no. of electrons =15 \[B.O=2.5\] Mag. Behaviour = Paramagnetic For \[N{{O}^{+}}\] Total no. of electrons = 14 B.O=3 Mag. Behaviour = Diamagnetic
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