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JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना Question Bank Self Evaluation Test - Chemical Bonding and Molecular Structure

  • question_answer
    CaO and \[~NaCl\] have the same crystal structure and approximately the same ionic radii. If U is the lattice energy of \[~NaCl\], the approximate lattice energy of \[CaO\] is     

    A) U/2                  

    B) U    

    C) 4C       

    D) 2 U

    Correct Answer: C

    Solution :

    [c] \[Lattice\text{ }energy=\frac{Product\text{ }of\text{ }charges}{interionic\text{ }distance}\] In \[NaCl\]the product of charges\[=1\times 1\]; In CaO product of charges \[=2\times 2=4\] while the inter ionic distance is almost same in both. Thus lattice energy of CaO is almost four times the lattice energy of\[NaCl\].                   


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