question_answer

Sulphur reacts with chlorine in 1 : 2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. What is the hybridisation state of central atom in the compound.

A) \[s{{p}^{3}}\]  

B) \[s{{p}^{2}}\]  

C) sp                                

D) \[ds{{p}^{2}}\]

Correct Answer: A

Solution :

[a] Hybridization of \[{{H}_{2}}S{{O}_{3}}=\frac{1}{2}(6+2+0)=4=s{{p}^{3}}\]