A) \[FeC{{l}_{2}}\]
B) \[ZnC{{l}_{2}}\]
C) \[CdC{{l}_{2}}\]
D) \[MgC{{l}_{2}}\]
Correct Answer: B
Solution :
[b] Polarizing power of \[Z{{n}^{2+}}\] is more than others, hence \[ZnC{{l}_{2}}\] is least ionic in nature.
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