JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना Question Bank Self Evaluation Test - Chemical Bonding and Molecular Structure

  • question_answer
    In piperidine the hybrid state assumed by N is

    A) \[sp\]                

    B) \[s{{p}^{2}}\] 

    C) \[s{{p}^{3}}\]             

    D) \[ds{{p}^{2}}\]

    Correct Answer: C

    Solution :

    [c] Hybridization of \[N={\scriptstyle{}^{1}/{}_{2}}\,\,[5+3+0-0]=4\] hence \[s{{p}^{3}}\]


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