A) \[N{{H}_{3}}\] is more basic than \[P{{H}_{3}}.\]
B) \[N{{H}_{3}}\] has a higher boiling point than that of HF.
C) \[{{N}_{2}}\]is less reactive than\[{{P}_{4}}\].
D) The dipole moment of \[N{{H}_{3}}\] is less than that of \[S{{O}_{2}}\].
Correct Answer: B
Solution :
[b] Due to high EN of F than N, H-bonding is stronger in HF than \[N{{H}_{3}}\] thus b.pt. of\[HF>N{{H}_{3}}\]
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