A) \[{{H}_{2}}C=CH-C\equiv N\]
B) \[HC\equiv C-C\equiv CH\]
C) \[{{H}_{2}}C=C=C=C{{H}_{2}}\]
D)
Correct Answer: A
Solution :
[a] \[\begin{align} & C{{H}_{2}}=CH-C\equiv N \\ & 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\,\,\,\,\,\,\,\,\,\,3\,\,\,\,\,\,\,\,4 \\ \end{align}\] \[3\,\sigma \] bonds (\[s{{p}^{2}}\]hybridisation); \[2\,\sigma \] bonds (sp-hybridisation) \[{{C}_{1}}=3\sigma \] bonds, \[{{C}_{2}}=3\,\sigma \]bonds, \[{{C}_{3}}=2\,\sigma \]bonds
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