A) 2, 3, 1
B) 1, 2, 3
C) 4, 1, 2
D) 3, 2, 1
Correct Answer: D
Solution :
[d] In \[Xe{{F}_{2}}\] Total number of valence electrons of\[Xe=8\], two electrons shared with 2F atoms, 6 electrons left hence 3 lone pairs, in \[Xe{{F}_{4}}\] 4 shared with 4 F atoms 4 left hence 2 lone pairs; in \[Xe{{F}_{6}}\]6 shared with 6 F atoms 2 left hence 1 lone pair.
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