A) \[{{N}_{2}}>O_{_{2}}^{-}>{{O}_{2}}\]
B) \[O_{_{2}}^{-}>{{O}_{2}}>{{N}_{2}}\]
C) \[{{N}_{2}}>{{O}_{2}}>O_{2}^{-}\]
D) \[{{O}_{2}}>O_{2}^{-}>{{N}_{2}}\]
Correct Answer: C
Solution :
[c] The bond order of \[{{N}_{2}}\text{, }{{O}_{2}},\]and \[O_{_{2}}^{-}\] are respectively 3, 2 and 1.5 Since higher bond order implies higher bond dissociation energy hence the correct order will be \[{{N}_{3}}>{{O}_{2}}>O_{2}^{-}\]
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