JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना Question Bank Self Evaluation Test - Chemical Bonding and Molecular Structure

  • question_answer
    In the reaction \[2PC{{l}_{5}}\rightleftharpoons PCl_{_{4}}^{-}+PCl_{6}^{-}\], the change in hybridization is from

    A) \[s{{p}^{3}}d\] to \[s{{p}^{3}}\]and \[s{{p}^{3}}{{d}^{2}}\]

    B) \[s{{p}^{3}}d\] to\[~s{{p}^{2}}\] and \[s{{p}^{3}}\]

    C) \[s{{p}^{3}}d\] to \[s{{p}^{3}}{{d}^{2}}\] and \[s{{p}^{3}}{{d}^{3}}\]

    D) \[s{{p}^{3}}{{d}^{2}}\]to \[s{{p}^{3}}\] and \[s{{p}^{3}}d\]

    Correct Answer: A

    Solution :

    [a]  \[\begin{align}   & \begin{matrix}    2PC{{l}_{5}}\rightleftharpoons PCl_{4}^{+}+PCl_{6}^{-} & {}  \\ \end{matrix} \\  & \begin{matrix}    \uparrow \,s{{p}^{3}}d & \uparrow \,s{{p}^{3}} & \uparrow \,s{{p}^{3}}{{d}^{2}}  \\ \end{matrix} \\ \end{align}\]


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