A) \[{{H}_{3}}\overset{+}{\mathop{N}}\,C{{H}_{2}}\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,NH\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,HC{{\bar{O}}_{2}}\]
B) \[{{H}_{3}}\overset{+}{\mathop{N}}\,\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,NH\underset{{}}{\mathop{\underset{{}}{\mathop{C}}\,}}\,{{H}_{2}}C{{\overset{-}{\mathop{O}}\,}_{2}}\]
C) \[{{\overset{-}{\mathop{O}}\,}_{2}}C\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,HNH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{{}}{\mathop{\underset{{}}{\mathop{C}}\,}}\,{{H}_{2}}\overset{+}{\mathop{N}}\,{{H}_{3}}\]
D) \[{{\overset{-}{\mathop{O}}\,}_{2}}CC{{H}_{2}}NH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H\overset{+}{\mathop{N}}\,{{H}_{3}}\]
Correct Answer: A
Solution :
[a] By convention, the amino acid with the free amino group (N-terminal) is written at the left end and the one with the unreacted carboxyl group (C-terminal) at the right end. Thus, the structure of Gly. Ala is \[{{H}_{3}}\overset{+}{\mathop{N}}\,C{{H}_{2}}\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,NH\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,HC{{\overset{-}{\mathop{O}}\,}_{2}}\]
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