A) \[{{C}_{1}}\] and \[{{C}_{4}}\]
B) \[{{C}_{1}}\]and \[{{C}_{5}}\]
C) \[{{C}_{1}}\] and \[{{C}_{6}}\]
D) \[{{C}_{2}}\] and \[{{C}_{6}}\]
Correct Answer: B
Solution :
[b] Glucose exists as glucopyranose (a six membered ring structure) which is formed through \[{{C}_{1}}\] and \[{{C}_{5}}\].You need to login to perform this action.
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