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JEE Main & Advanced Physics Atomic Physics Question Bank Self Evaluation Test - Atoms

  • question_answer
    When an electron in a hydrogen atom makes a transition from 2nd excited stated to ground state it emits a photon of frequency/ The frequency of photon emitted when an electron of \[L{{i}^{++}}\] makes transition from Ist excited state to ground state is

    A)  \[\frac{243}{32}f\]

    B)  \[\frac{141}{32}f\]

    C)  \[\frac{81}{32}f\]         

    D)  \[\frac{63}{32}f\]

    Correct Answer: A

    Solution :

    [a] \[E=hf=13.6{{Z}^{2}}\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)\] \[\frac{{{f}_{1}}}{{{f}_{2}}}=\frac{{{3}^{2}}\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)}{{{1}^{2}}\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{3}^{2}}} \right)}\Rightarrow {{f}_{2}}=\frac{243}{32}f.\]


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