question_answer

A neutron of kinetic energy 65eV collides in elastically with a singly ionized helium atom at rest. It is scattered at an angle of \[90{}^\circ \]with respect of its original direction. If the atom get de-excited subsequently by emitting radiation, then the impossible frequency of the emitted radiation is  [Given: Mass of \[He\]atom = 4\[\times \](mass of neutron), Ionization energy of  atom =13.6eV]

A)  \[1.82\times {{10}^{15}}Hz\]

B)  \[6.11\times {{10}^{15}}Hz\]

C)  \[11.67\times {{10}^{15}}Hz\]

D)  \[9.84\times {{10}^{15}}Hz\]