A) \[\frac{3{{q}^{2}}}{2{{\varepsilon }_{0}}h}\]
B) \[\frac{3{{q}^{2}}}{4{{\varepsilon }_{0}}h}\]
C) \[\frac{3q}{2\pi {{\varepsilon }_{0}}h}\]
D) \[\frac{3q}{4\pi {{\varepsilon }_{0}}h}\]
Correct Answer: A
Solution :
[a] \[\frac{m{{v}^{2}}}{r}=\frac{3{{q}^{2}}}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\Rightarrow mvr=\frac{3{{q}^{2}}}{4\pi {{\varepsilon }_{0}}v}\] ?.(i) and \[\frac{nh}{2\pi }=mvr\] ?(ii) Using (i) and (ii) and putting n=1 \[\frac{h}{2\pi }=\frac{3{{q}^{2}}}{4\pi {{\varepsilon }_{0}}v}\Rightarrow v=\frac{3{{q}^{2}}}{2{{\varepsilon }_{0}}h}\]
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