A) \[15\times {{10}^{6}}\]
B) \[\frac{3}{5}\times {{10}^{6}}\]
C) \[\frac{5}{9}\times {{10}^{6}}\]
D) None of these
Correct Answer: C
Solution :
[c] \[N\propto \frac{1}{{{\sin }^{4}}\theta /2};\frac{{{N}_{2}}}{{{N}_{1}}}=\frac{{{\sin }^{4}}\left( {{\theta }_{1}}/2 \right)}{{{\sin }^{4}}\left( {{\theta }_{2}}/2 \right)}\] \[\text{or }{{N}_{2}}=5\times {{10}^{6}}\times {{\left( \frac{1}{2} \right)}^{4}}{{\left( \frac{2}{\sqrt{3}} \right)}^{4}}=\frac{5}{9}\times {{10}^{6}}\]
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