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JEE Main & Advanced Physics Atomic Physics Question Bank Self Evaluation Test - Atoms

  • question_answer
    An \[\alpha \]-particle of 10 MeV collides head-on with a copper nucleus (Z=29) and is deflected back. Then, the minimum distance of approach between the centers of the two is:

    A)  \[8.4\times {{10}^{-15}}cm\]

    B)  \[8.4\times {{10}^{-15}}m\]

    C)  \[4.2\times {{10}^{-15}}m\]

    D)  \[4.2\times {{10}^{-15}}cm\]

    Correct Answer: B

    Solution :

    [b] Not Available        


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