A) 54.4 eV
B) 13.6eV
C) 40.8 eV
D) 27.2 eV
Correct Answer: A
Solution :
[a] Excitation energy \[\Delta E={{E}_{2}}-{{E}_{1}}=13.6{{Z}^{2}}\] \[\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right]\] \[\Rightarrow 40.8=13.6\times \frac{3}{4}\times {{Z}^{2}}\Rightarrow \,=2.\] Now required energy to remove the electron from ground state \[=\frac{+13.6{{Z}^{2}}}{{{\left( 1 \right)}^{2}}}=13.6{{\left( Z \right)}^{2}}=54.4eV.\]
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