2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Atomic Physics

JEE Main & Advanced Physics Atomic Physics Question Bank Self Evaluation Test - Atoms

  • question_answer
    An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is

    A)  38.2

    B)  49.2 

    C)  51.8

    D)  79.0

    Correct Answer: D

    Solution :

    [d] For helium ion, Z=2 and for first orbit n=1 \[\therefore E{{ & }_{1}}=\frac{-13.6}{{{\left( 1 \right)}^{2}}}\times {{2}^{2}}=-54.4eV\] \[\therefore \]Energy required to remove this \[{{e}^{-}}=+54.4eV\] \[\therefore \]Total energy required\[=54.4+24.6=79eV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner