2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Atomic Physics

JEE Main & Advanced Physics Atomic Physics Question Bank Self Evaluation Test - Atoms

  • question_answer
    A hydrogen atom in state n=6 makes two successive transitions and reaches the ground state. In the first transition a photon of 1.13 eV is emitted. Find the energy of the photon emitted in the second transition and the value of n in the intermediate state.

    A)  12.1eV, n=3

    B)  6.1eV, n=4

    C)  2.1eV, n=3

    D)  1.1eV, n=5.

    Correct Answer: A

    Solution :

    [a] Not Available


You need to login to perform this action.
You will be redirected in 3 sec spinner