A) 60
B) 32
C) 4
D) 64
Correct Answer: A
Solution :
[a] The maximum number of electron is in an orbit is \[2{{n}^{2}}.\text{ }n>4\] is not allowed. Therefore the number of maximum electron that can be in first four orbits are \[2{{\left( 1 \right)}^{2}}+2{{\left( 2 \right)}^{2}}+2{{\left( 3 \right)}^{2}}+2{{\left( 4 \right)}^{2}}\] \[=2+8+18+32=60\] Therefore, possible element are 60.
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