JEE Main & Advanced Mathematics Definite Integration Question Bank Self Evaluation Test - Application of Integrals

  • question_answer
    The value of c + 2 for which the area of the figure bounded by the curve\[y=8{{x}^{2}}-{{x}^{5}}\], the straight lines \[x=1\] and \[x=c\] and x-axis is equal to \[\frac{16}{3},\] is

    A) 1

    B) 3

    C) -1

    D) 4

    Correct Answer: A

    Solution :

    [a] (1) For \[c<1,\int_{c}^{1}{(8{{x}^{2}}-{{x}^{5}})dx=\frac{16}{3}}\] \[\Rightarrow \frac{8}{3}-\frac{1}{6}-\frac{8{{c}^{3}}}{3}+\frac{{{c}^{6}}}{6}=\frac{16}{3}\] \[\Rightarrow {{c}^{3}}\left[ -\frac{8}{3}+\frac{{{c}^{3}}}{6} \right]=\frac{17}{6}\]. Again, for \[c\ge 1,\] none of the values of c satisfy the required condition that \[\int_{1}^{c}{(8{{x}^{2}}-{{x}^{5}})dx=\frac{16}{3}\Rightarrow c+2=1}\].


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